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Sample Question Paper Quantitative Solution 02

1.
Since, six technicians working at the same rate completely work of one server in 10 H.
Hence, total work= 10 x 6 = 60 man hours.
Now, from 11.oo am to 5 pm total man hours= 6 x 6 = 36
From, 5 pm to 6 pm total man hours = 7
From, 6 pm to 7 pm total man hours =8
From, 7 pm to 8 pm  total man hours =9
Total: 60 Hours.
Hence, the work will be completed at 8 pm.
(D)
2.
Firstly, make a table taking Persons(p1, p2, p3….p6) as rows and tasks(t1, t2, t3…) as columns.
Go through the question again and draw the final table considering all the statements.
First task can be done in 3 ways by 3 persons.
Second task can be given to two person i.e. ( 3 and 4)
Number of ways=2
Third task can be done by 4 person i.e. 4 ways.
Similarly, for fourth, fifth and sixth tasks, number of ways are 3, 2, 1 and respectively.
Total number of ways= 2 x 3 x 4 x 3 x 2 x 1 = 144
(A)
3.(D)
4.
Let the number of students in the front row be x and number of rows be n.
Hence, number of students in the next rows would be (x – 3), (x – 6), (x – 9),….. and so on…
If n, i.e. number of rows be 3, then number of students
=x + (x – 3) + (x – 6) = 630
i.e. 3x = 639 i.e. x= 213 (Thus n=3 possible)
Likewise, if n=4,
then x + (x – 3) + (x – 6) +(x – 9) = 630
i.e.  4x – 18 = 630 i.e. x= 162
(Thus, n=4 is also possible)
If n=5, then
x + (x – 3) + (x – 6) + (x – 6) + (x – 9) + ( x – 12) = 630
i.e. 5x- 30= 630
5x = 660 i.e. x= 132
(Thus, n=5 is also possible)
If n=6 then 6x= 675
In this case value of x cannot be a integer.
Therefore, n=6 is not possible.
(D)
5.
The shaded portion represents the area which shows people who do not watch DD channel. Since 80% watch DD hence 20% do now watch DD. Let those who watch BBC and CNN only x% then .
12+10-x=20
Hence x= 2
Sample_Question_paper_Solution_02Q_05
6.
Let x, y and z be the hundredth, tens and unit digits of the original number.
According to question,
(100z + 10y + x) – ( 100x + 10y + z) = 594
99(z-x)= 594
(z-x)=6
So, the possible values of (x, z) are (1, 7), (2, 8), and (3, 9)
Again, the tens digit can have any values from 0, 1, 2, 3, … 9
Hence. Minimum value of their sum= x + y + z = 1 + 0 + 7 = 8
(C)
7.
223 + 233 + 243 + 253 +……+ 873 + 883
On rearranging = (22 3 +883) + (233 + 873) + (243 + 863)+……..(543 + 563) + 553
Now, we know that an + bn  is divisible by (a + b) when n is odd number.Therefore, all the terms except 553, is divisible by 110.
Now, the remainder when 553 is divided by 110 is 55
Hence the required remainder when whole expression is divided by 110 is 55.
8.
Total number of passenger in the Rajdhani Express=10 x 20=200
So, in the 9 boggies the minimum number of total passengers
=12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 144
Hence minimum number of passengers in one boggie can be (200 – 144) = 56
(C)
9.
Let the number of men be 100.
Then, Men x Time= Work
100 x 1 = 100 unit.
Amount of work increased by 50%
New work= 150 unit
as the planned time remains same i.e. 1
Then men required will be 150 i.e. 50 more workers.
but since new workers are 25% efficient i.e. 5/4 times efficient as existing workers.
Actual number of workers= 50/(5/4)= 40 men
Required percent(%)= (40/1oo) x 100 = 40%
10.
For a given volume i.e. 64 cm3
Cube has minimum surface are of length of edge=4 cm.
Its diagonal= 4 x ( sq root 3).
(C)

Answers

Sample Question Paper Quantitative 02

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5 comments

  1. Rishabh Mishra

    qus no 2_=- Answer would be 192

    T1= 4 ways
    T2= 2 ways
    T3= 4 ways
    T4=3 ways
    T5= 2 ways
    T6=1 way
    toatal ways= 4*2*4*3*2*1
    = 192

  2. anish

    Q3: 100 forward
    96 back (because next stone is at 96 , 2m away from first that is at 98)
    96 forward
    94 back
    94 forward
    92 back
    92 forward
    90 back
    90 forward
    total= 844

  3. anish

    qus no 2_=- Answer would be 192

    T1= 3 ways because t2 has already fixed person either 3 or 4. so left with one from 3 or 4 and 5, 6
    T2= 2 ways
    T3= 4 ways
    T4=3 ways
    T5= 2 ways
    T6=1 way
    total ways= 3*2*4*3*2*1
    = 144

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