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Cryptarithmetic Problem 7

Cryptarithmetic_Problem_7

1. Which of the following forms the right angled triangle ? 
(a) S, G, Q (b) S, G, P (c) Q, P, A (d) R, S, C
2. Value of C ? 
(a) 5 (b) 6 (c) 7 (d) 8
3. Value of 2Q + D ? 
(a) 15 (b) 16 (c) 17 (d) 18

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12 comments

    1. ElitmusZone Post author

      Hello Naresh,
      We didn’t understood your requirements.

      full solve paper???

      Please elaborate your comments.
      Thanks for co-operations

  1. saumya

    Here in this ques while predicting the value of D how can we say that carry over Q will be 1 only … It can be 2 or 3…

    1. aishwary

      take A as maximum ,let say 9 ….it will pass 2 to the next line…now you take any value of P and G between (1 to 8) it will never pass more than 1 carry to the next step….

    1. Aman

      @Varun
      If u take D=5 then multiplying it by S would give C…C has to be either be 0 or 5 (anythng multiplied by 5 gives 0 or 5)..C cnnot be 5 as D is already 5…and it cannot be 0 also as R=0 already..
      So we cnnot take D=5.

    2. gaurav kumar

      look in multiplication in the last Q+1=D
      look in 3rd question 2Q+D we have to solve….
      2Q+D= 2Q+Q+1=3Q+1
      no check options 3Q+1 will be 16 only so Q will be 5 and D will be 6

  2. bhawinee

    i dont understand a question asked in cryptairthmetic, even after finding out all the values, i am not able to answer this question.

    The que is : Which of the following forms the right angled triangle ?
    (a) S, G, Q (b) S, G, P (c) Q, P, A (d) R, S, C
    how to answer this problem please elaborate.

    1. vikash

      what will be the answer of this question please explain.

      Which of the following forms the right angled triangle ?
      (a) S, G, Q (b) S, G, P (c) Q, P, A (d) R, S, C

        1. Ravi

          In this problem why Q is fixed by value 5 why it is not considered as either 2,4,6,8

          We can also fix the value of D

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