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ElitmusZone » Cryptarithmetic Problem 5

# Cryptarithmetic Problem 5 1. Value of  S ? (a) 6 (b) 7 (c) 8 (d) 9
 2. Which of the following follows the Pythagoras theorem ? (a) H, A, D (b) H, A, B (c) T, E, A (d) T, E, D
 3. Value of H + R + S + A ? (a) 14 (b) 15 (c) 16 (d) 17

Video Solution

1. Gokul

In the first case that is predicting ‘A’, the value of A can be 1 as well apart from being 5 or 6. Why 1 is not considered for A?

1. ElitmusZone Post author

Suppose A={1, 5, 6} Reference: A x A= _A [H R S A ]
Let’s take A=1
then,
T  E  A
x  A
H  R  S   A

T  E  1
x   1
H  R  S  1 [ T  E  1  ]
If you will multiple any number with 1, result will be number itself.
A B C
x 1
A B C
Detailed Explanation( Rule 2)

2. Yash

sir How L=2 is not explained in detail

1. shraddha tiwari

when E=1 it a trick that the carry of two digits will always be 1…so from there the value of L =2 is evaluated.

3. Tushar garg

Why E=1 not any other value initially we take?

1. ElitmusZone Post author

Hello Tushar,

This is just an hit and trial approach with the values of E.

So, you have to make a set of possible values of E.

Here E can be {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

Now, as you have already considered R=0 and A=5

So, the possible values of E= {1, 2, 3, 4, 6, 7, 8, 9}

Now you have to start hit and trial with the possible values of E from above set.

So, firstly consider E=1 proceed further ……

Best Regards,
ElitmusZone Team

1. Soumya Chowdhury

Suppose I take E=2,4,6 or 8 then the value of S=2 comes. This value dosent satisfy the next step. But what if we take E=3,7 or 9, then the value os S=7. How will I jnow about wrong step

4. Sudeep

‘A’ shouldn’t be considered in {2, 4, 8} in step-2. {2, 4, 8} for A, don’t satisfy A X A= _A (in step 1). Hence there is only one case, i.e, A=5

5. vencut

y not H=9 ? and how it came S value. what do u mean by side by side ? i didnt get.

1. ElitmusZone Post author

You can take H=9 and check whether it satisfies the solution or not.