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ElitmusZone » Cryptarithmetic Problem 5

# Cryptarithmetic Problem 5

 1. Value of  S ? (a) 6 (b) 7 (c) 8 (d) 9
 2. Which of the following follows the Pythagoras theorem ? (a) H, A, D (b) H, A, B (c) T, E, A (d) T, E, D
 3. Value of H + R + S + A ? (a) 14 (b) 15 (c) 16 (d) 17

Video Solution

1. Gokul

In the first case that is predicting ‘A’, the value of A can be 1 as well apart from being 5 or 6. Why 1 is not considered for A?

1. ElitmusZone Post author

Suppose A={1, 5, 6} Reference: A x A= _A [H R S A ]
Let’s take A=1
then,
T  E  A
x  A
H  R  S   A

T  E  1
x   1
H  R  S  1 [ T  E  1  ]
If you will multiple any number with 1, result will be number itself.
A B C
x 1
A B C
Detailed Explanation( Rule 2)

when E=1 it a trick that the carry of two digits will always be 1…so from there the value of L =2 is evaluated.

1. ElitmusZone Post author

Hello Tushar,

This is just an hit and trial approach with the values of E.

So, you have to make a set of possible values of E.

Here E can be {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

Now, as you have already considered R=0 and A=5

So, the possible values of E= {1, 2, 3, 4, 6, 7, 8, 9}

Now you have to start hit and trial with the possible values of E from above set.

So, firstly consider E=1 proceed further ……