#### ElitmusZone

ElitmusZone » Cryptarithmetic Problem 4

# Cryptarithmetic Problem 4

 1. Value of W + H + Y ? (a) 7 (b) 8 (c) 9 (d) 10
 2. Value of B ? (a) 1 (b) 2 (c) 3 (d) 4
 3. Value of N + U + T ? (a) 17 (b) 18 (c) 19 (d) 20

Can u plz explain how the possible values of N = {7,8,9}.
You have note discussed about B .

1. Amarpal Singh

because B+U<=9 and B+U=N
and value of u=6
then B may be 1,2,3 if B=1 then N=6+1=7
b=2 then N=8 and B=3 then N=9

2. rajan

actually ,B + 6 = N , is not creating any carry otherwise ,at last B would not be B.
So,if (B + 6 + (0 or 1 or 2) = N)
then, N < 9 ,so possible values of, N={7, 8, 9}
now if carry =0 ; B ={ 1, 2 ,3}
else if carry = 1;B = { 0 , 1, 2}
else if carry = 2 ;B={ 0 ,1} and N = { 8, 9}

1. Karan

according to rule 3, y*u=_y
if y=5, u={3,7,9}
or if u=6, y={2,4,8}
if y=5, then y*any_number=’_0′ or’_5′, i.e two possibilities for unit case,
but in this case,
y*t=_p
y*u=_y
y*n=_a
creating three possibilities, which means y!=5.

1. ElitmusZone Post author

In the solution of the problem we taken two cases (Case1 and Case2) at the beginning of the solution.
Case-1 When Y={2, 4, 8} and U={6}
Case-2 When Y={5} and U={3, 7, 9}

We have to do hit and trial with the both the cases. You can also take Case1 and proceed. Later on, Y=5 will get rejected.

(We haven’t made any assumption while providing solution to this Cryptarithmetic Problem.)

2. Amarpal Singh

We have U*Y=Y
if we take u=5
then
5*1=5(not 1),5*2=0(not 2),5*3=5(not 3)……………means right digit never come
but in case of u=6
6*2=12(means 2)
6*4=24(means 4)
6*8=48(means 8)

2. karan

these type of questions can only be solved by trial and error method .you have to take values from options to get a answer otherwise you will get stuck in those problems.

1. surya

1,4,6,7,8 are already assigned.remaining are 2 ,3,5,9 and we have left most value as 16 if we take ”w” as 3 or above the value of left most two digits exceeds 16 so 2 is the best choice for “w”

1. Soumya Chowdhury

Thats my question. If we take the wrong value, we must know where to find the wrong value

3. Soumya Chowdhury

2 H 4
x 7 6 T
1 1 7 P
1 4 P 4
1 6 H 8
1 7 E P 1 P

” Now you can easily predict other values.
Value of T=5 and P=0 ”
How we can predict T and P in the last stage?