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ElitmusZone » Cryptarithmetic Problem 4

# Cryptarithmetic Problem 4 1. Value of W + H + Y ? (a) 7 (b) 8 (c) 9 (d) 10
 2. Value of B ? (a) 1 (b) 2 (c) 3 (d) 4
 3. Value of N + U + T ? (a) 17 (b) 18 (c) 19 (d) 20

1. Chandrajeet Yadav

Can u plz explain how the possible values of N = {7,8,9}.
You have note discussed about B .

1. Amarpal Singh

because B+U<=9 and B+U=N
and value of u=6
then B may be 1,2,3 if B=1 then N=6+1=7
b=2 then N=8 and B=3 then N=9

2. rajan

actually ,B + 6 = N , is not creating any carry otherwise ,at last B would not be B.
So,if (B + 6 + (0 or 1 or 2) = N)
then, N < 9 ,so possible values of, N={7, 8, 9}
now if carry =0 ; B ={ 1, 2 ,3}
else if carry = 1;B = { 0 , 1, 2}
else if carry = 2 ;B={ 0 ,1} and N = { 8, 9}

1. Karan

according to rule 3, y*u=_y
if y=5, u={3,7,9}
or if u=6, y={2,4,8}
if y=5, then y*any_number=’_0′ or’_5′, i.e two possibilities for unit case,
but in this case,
y*t=_p
y*u=_y
y*n=_a
creating three possibilities, which means y!=5.

2. vidyadhar

hello rajan crypth.is very difficult topic ,plz help me

2. kavitha

1. ElitmusZone Post author

In the solution of the problem we taken two cases (Case1 and Case2) at the beginning of the solution.
Case-1 When Y={2, 4, 8} and U={6}
Case-2 When Y={5} and U={3, 7, 9}

We have to do hit and trial with the both the cases. You can also take Case1 and proceed. Later on, Y=5 will get rejected.

(We haven’t made any assumption while providing solution to this Cryptarithmetic Problem.)

2. Amarpal Singh

We have U*Y=Y
if we take u=5
then
5*1=5(not 1),5*2=0(not 2),5*3=5(not 3)……………means right digit never come
but in case of u=6
6*2=12(means 2)
6*4=24(means 4)
6*8=48(means 8)

3. karan

these type of questions can only be solved by trial and error method .you have to take values from options to get a answer otherwise you will get stuck in those problems.

4. N Srikanth kumar

i.e. N+6=B and further, can any one explain this point please,

5. N SRIKANTH KUMAR

6. Pranjal

how N+6=B?
n even if it is true then in answer how come N=7 and B=1?

1. Soumya Chowdhury

B+6=N and not N+6=B

7. jagadeesh

Can anyone ex

8. jagadeesh

Can anyone explain how W=2

1. surya

1,4,6,7,8 are already assigned.remaining are 2 ,3,5,9 and we have left most value as 16 if we take ”w” as 3 or above the value of left most two digits exceeds 16 so 2 is the best choice for “w”

9. Raj

Why we have taken ONLY this case I.e N=7 and Y=4, why not N=8 Y=2

1. Raj

Sorry N=8 and Y = 4… Plz explain this case

1. Soumya Chowdhury

Thats my question. If we take the wrong value, we must know where to find the wrong value

10. Soumya Chowdhury

2 H 4
x 7 6 T
1 1 7 P
1 4 P 4
1 6 H 8
1 7 E P 1 P

” Now you can easily predict other values.
Value of T=5 and P=0 ”
How we can predict T and P in the last stage?