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ElitmusZone » Cryptarithmetic Problem 2

# Cryptarithmetic Problem 2 1. Value of N ? (a) 2 (b) 4 (c) 3 (d) 8
 2. Value of T + 2E ? (a) 15 (b) 17 (c) 16 (d) 11
 3. Which of the following forms Right Angled Triangle ? (a) N, P, E (b) T, P, E (c) T, H, A (d) B, N, S

1. Anusha

why we took i=0?
can any one explain?

1. ElitmusZone Post author

[If you multiply to any number with 5, you will only get [0, 5] as their last digit.]
(5 x even =_0 and 5 x odd=_5)
and we have already taken value of E=5. So, only one possibility for the value of I.
Therefore value of I=0.

1. N Srikanth kumar

thank you for explaining how i=0

2. Elan

I can’t able to read solutions.. wat wil do?? Plz anyone help me..!!

1. Pritam Sinha

Tutorial of cryptarithmetic is really helpfull. Give time to well understand tutorial after that i’m 100% sure you can easily solve the problem. After the cryptarithmetic tutorial it need to be understand unit digit method then only you can solve any problem of cryptarithmetic.

3. Bala

why not take E as 1,since ExE=(1,5,6).why only (5,6)

1. RAKESH

if u multiply a 3 digit number to one the multiplication will also be 3 digit number but in the problem multiplication is 4 digit number. ex–THE*E=PIAE; for the value E=1 multiplication will be THE…

1. ElitmusZone Post author

You can value of E=1 as well. But later on, E=1 will get rejected.

Please go through the explanation of Rakesh.

4. neha

Hello Admin… M very bad in cryptography,, as I wrote elitmas bt my PS marks was too bad. Cryptography is one of the better part in ps.. If I will practice these questions available on ur sites,, will it be beneficial ??? 7 Aug is my test date. Kindly help what to do for PS.

5. Prasuna

Please explain why p={ 3, 7, 9} only

6. Pranjal

how can we deduce T=6 by 5*T=30 ?
why are we not considering possibility of remainder there in T*H?

1. ElitmusZone Post author

Hi Pranjal.

Query 1:how can we deduce T=6 by 5*T=30 ?

Only one possible value of T exits. 5 x 6 = 30… ( Just write the mulitplication table of 5 in detail and analyse all the possible cases. 🙂

Query 2: why are we not considering possibility of remainder there in T*H?

There is no possibility of Remainder in T * H .

(2) T H 5
x 5
3 0 A 5

You have already taken I=0. If you will get any remained in T * H Multiplication, then value of I cannot be equal to zero. If you have any remaider then value of I can be 1,2,3,4,

Best Regards,
Elitmuszone Team

7. Ankit Kumar

T = 6
H = 1
E = 5
P = 3
N = 4
S = 2
I = 0
A = 7
B = 8

8. jagadeesh

Can you please clarify after second division of problem into 3 parts which case your considered it should be case 3 but you explained solution using case 2

9. Muhammad Tayyab

anybody tell me what are the answer of this cryptarithmetic problem.

SEND
*THE
———–
MONEY

10. MD IRFAN

if we take p=6, then the possible value of E=2,4,8 , but if we multiply E*E is should be give last digit E so in option 2,4 and 8 don’t give 2,4 and 8 respectively its also reject means p=6.then why you take p=6.

11. Manvendra

can u please explain the solution of third question

1. ElitmusZone Post author

Please check which of the following combination of numbers follows Pythagoras Theorem.
a2+b2=c2