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Cryptarithmetic Multiplication 33

Cryptarithmetic_Multiplication_33

1. Which of the following set contains only even numbers ? 
(a) M, X, A (b) A, V, L (c) X, L, W (d) P, W, S
2. Value of M ? 
(a) 9 (b) 8 (c) 2 (d) 3
3. Which of the following set contains prime numbers only ?
(a) A, V, P (b) M, X, A (c) A, V, L (d) S, P, W
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7 comments

      1. SHEETAL KHATRI

        Solution:
        1. L * A=0
        2. V*A=A
        3. X*A=0
        We can conclude that A=5
        and using 2nd case we can say if A=5 then V=(3,7,9)
        M X A
        *L
        A L V 0
        cases: 1. A=5 L=2; 2. A=5 L=4; 3. A=5 L=6; 4. A=5 L=8

        Using case 1: A=5 L=2
        MX5
        2
        52V0. NOT POSSIBLE CASE FAILS

        Case2 will also fail as when 4 gets multiplied with M ,it will never produce a number in 50’s.

        Case 3:
        A=5 L=6
        MX5
        6
        56V0. M=9 X=4 V=7

        MXA
        *V
        LL?A. We’ll obtain ?=1

        Solving whole: P=3. S=8

        9 4 5
        *4 7 6
        5 6 7 0
        6 6 1 5
        3780
        449820

  1. rony

    A * L and A * X both result in unit place = 0 , this implies that A=0.
    next in M X A * A = P V S O, take X=4(hit and trial) , it gives S = 8. now take M X A* L and put the obtained values in it. Follow the procedure now its easy to find.

  2. SHEETAL KHATRI

    Solution:
    1. L * A=0
    2. V*A=A
    3. X*A=0
    We can conclude that A=5
    and using 2nd case we can say if A=5 then V=(3,7,9)
    M X A
    *L
    A L V 0
    cases: 1. A=5 L=2; 2. A=5 L=4; 3. A=5 L=6; 4. A=5 L=8

    Using case 1: A=5 L=2
    MX5
    2
    52V0. NOT POSSIBLE CASE FAILS

    Case2 will also fail as when 4 gets multiplied with M ,it will never produce a number in 50’s.

    Case 3:
    A=5 L=6
    MX5
    6
    56V0. M=9 X=4 V=7

    MXA
    *V
    LL?A. We’ll obtain ?=1

    Solving whole: P=3. S=8

    9 4 5
    *4 7 6
    5 6 7 0
    6 6 1 5
    3780
    449820

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