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Cryptarithmetic Multiplication 30

Cryptarithmetic_MULTIPLICATION_30

1. Value of M ? 
(a) 6 (b) 5 (c) 4 (d) 3
2. Value of D + I + N ? 
(a) 15 (b) 16 (c) 17 (d) 18
3. Which of the following set form a right angle triangle ? 
(a) M, I, N (b) D, I, N (c) E, J, M (d) M, J, A
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3 comments

  1. PATOORI POOJITHA REDDY

    first you have to divide given problem into three parts –

    (1)E J M (2) E J M (3) E J M
    N I D
    —————- ——————- ——————

    M J A N S I A S I S S A
    —————- —————— ——————–

    Now, in (1)
    we have M*N=N It is possible either M=6(N=2 or 4 or 8) or N=5(M=3 or 7 or 9)
    first take N=5 and M=3
    E J 3
    5
    ————–
    3 J A 5
    ————–
    here possible of J are {0,1,2,4,6,7,8,9}
    try with J=0
    E 0 3
    5
    ————–
    3 0 1 5
    ————-
    Therefore E=6;

    6 0 3
    5
    ————-
    3 0 1 5
    ————–
    next in (3)

    D*M=A here A=1.It is possible 7*3=21 or 3*7=21
    therefore D=7

    6 0 3
    7
    ————-
    4 2 2 1
    —————

    here we get I=4

    therefore 6 0 3
    4
    ——————
    2 4 1 2
    —————–

    therefore E=6,J=0,M=3,D=7,I=4,N=5,K=9,A=1,S=2.

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