ElitmusZone » Cryptarithmetic Multiplication 27

3 comments

  1. shehzad

    in 3rd multiplication O*E = O, which means that either O is 5 and E is an odd no. or E is 6 nd O is an even number
    now check option 1 for case: O= 5, E odd no. whch gives only one possible value of E= 7.
    now check the third multiplication by using this vlues nd the question will be solved :
    A G 7
    * 5
    _______________
    G 5 T 5

  2. vikas solanki

    you can proceed like this

    0 + 0 + 0 =0,,this can only be possible if o =5 ,think with no carry from previous if we will consider carry thn no same value is possbile to give 0 +0 =9 since max carry from a +g can be 1 only so 0=5 for sure
    now O*E=E MEANS E IS ODD NUMBER AND IN ABOVE PROBLEM O+CARRY =E,THN CARRY MUST BE 2 AND E =7
    O*A =O,A ALSO ODD NUMBER POSSIBLE VALUES ARE{3,9} BECAUSE IT CANT BE {1,7,9}
    NOW SEE THE PROBLEM A*A G E = 3 DIGIT NUMBER MEANS A<=3 ,SINCE A*A IS LAST NUMBER AND GIVING NO CARRY
    SO VALUE OF A=3
    NOW PROCEED WITH THESE VALUES

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