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ElitmusZone » Cryptarithmetic Multiplication 26

# Cryptarithmetic Multiplication 26 1. Which of the following set contains only even numbers ? (a) M, X, A (b) A, V, L (c) X, L, W (d) P, W, S
 2. Which of the following set forms a right angle triangle ? (a) P, A, X (b) A, V, L (c) L, G, P (d) P, K, W
 3. Which of the following set contains prime numbers only ? (a) A, V, P (b) M, X, A (c) A, V, L (d) S, K, W

1. AADITYA DWIVEDI

945*476
1) C
2) A
3) A

2. A.Ramadevi

im not getting the solution pls any one explain this one

1. Neha Mittal

V*A=A So,A can be from either the set of {5} when V={3,7,9} or {2,4,8} when V={6}
but X*A=K and L*A=K .So, A can only be 5 and K=0 while X and L are from the set of even numbers.
P+1=X
V+A=W

3. Soumya Chowdhury

V * A = A which means either
A = 5 and V = (3,7,9) or A = (2,4,8) and V = 6
Multiplication of A with the number gives K and A only. This thing is possible in case of 5 where it gives 5 and 0 when multiplied by anyone .
Therefore A can be assuned to be 5 and K is 0.
Now from M X A * L = A L V K, we have M X 5 * L = 5 L V 0.
Now we can have L = any odd numbers (2, 4, 6, 8) Now L = 2, 4 cant be possible as multiplication of L with any value of M will yield maximum of 1 and 3 respectively as the value of A in the 1000th place.
So now we have
A = 5
K = 0
V = 3,7,9
X = 2,4,6,8
L = 6,8.
Now we have got two case
Case 1: L = 6 & X = 2,4,8.
Case 2: L = 8 & X = 2,4,6.
Now by hit and trial for Case 1 and Case 2 in M X 5 * 6 = 5 L V 0 , we can get it satisfies case 1 only for X = 4 and dont satisfies Case 2.
So we get
L=6
X=4
M=9
V=7
K=0
A=5.

Now put this vues and proceed further

4. Haridev Purve

945
*476
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