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Cryptarithmetic Multiplication 26

Cryptarithmetic_MULTIPLICATION-26

1. Which of the following set contains only even numbers ? 
(a) M, X, A (b) A, V, L (c) X, L, W (d) P, W, S
2. Which of the following set forms a right angle triangle ? 
(a) P, A, X (b) A, V, L (c) L, G, P (d) P, K, W
3. Which of the following set contains prime numbers only ?
(a) A, V, P (b) M, X, A (c) A, V, L (d) S, K, W
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4 comments

    1. Neha Mittal

      V*A=A So,A can be from either the set of {5} when V={3,7,9} or {2,4,8} when V={6}
      but X*A=K and L*A=K .So, A can only be 5 and K=0 while X and L are from the set of even numbers.
      P+1=X
      V+A=W

  1. Soumya Chowdhury

    V * A = A which means either
    A = 5 and V = (3,7,9) or A = (2,4,8) and V = 6
    Multiplication of A with the number gives K and A only. This thing is possible in case of 5 where it gives 5 and 0 when multiplied by anyone .
    Therefore A can be assuned to be 5 and K is 0.
    Now from M X A * L = A L V K, we have M X 5 * L = 5 L V 0.
    Now we can have L = any odd numbers (2, 4, 6, 8) Now L = 2, 4 cant be possible as multiplication of L with any value of M will yield maximum of 1 and 3 respectively as the value of A in the 1000th place.
    So now we have
    A = 5
    K = 0
    V = 3,7,9
    X = 2,4,6,8
    L = 6,8.
    Now we have got two case
    Case 1: L = 6 & X = 2,4,8.
    Case 2: L = 8 & X = 2,4,6.
    Now by hit and trial for Case 1 and Case 2 in M X 5 * 6 = 5 L V 0 , we can get it satisfies case 1 only for X = 4 and dont satisfies Case 2.
    So we get
    L=6
    X=4
    M=9
    V=7
    K=0
    A=5.

    Now put this vues and proceed further

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