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ElitmusZone » Cryptarithmetic Multiplication 24

# Cryptarithmetic Multiplication 24 1. Value of F ? (a) 5 (b) 6 (c) 7 (d) 8
 2. Value of E + W + T ? (a) 15 (b) 16 (c) 17 (d) 18
 3. Value of H ? (a) 4 (b) 5 (c) 6 (d) 7

1. preeti

how you have solved it?? i am not able to solve. please explain.

2. Raj

Can I have the solution please?

3. Sahil

846*573

4. Nikki

Hey buddy.. Please provide the detailed solution….

1. ethan

first take
F Y H
* W
—————–
E K Z Z

1. ethan

and check for unitplace test for 2
6*7 satifies the test

5. Lokesh Kumar

First divide into 3 parts by unit digit method
Take 2 part
F Y H
* W
—————–
E K Z Z

By unit digit method check for
Z=1 all cases doesn’t satisfy (check yourself)
Then
Z=2 make all the cases and start finding that cases will satisfy or not
You will find that H=6 and W=7 is looking appropriate.
Start solving take the value of T first start and u will see it will take t=3,9 start solving and rest value you can find yourself. I can provide the whole solution but it would be better, if you try yourself.

1. Lokesh Kumar

T=3 will satisfy rest is easy

2. Paresh

So why can’t we take H=4 and W=3 and Y=7

6. aditi

Why are we taking fyh*w first instead of checking for fyh*t??

7. Raj

8. Rohan Saxena

From option we can obtain that
h=4,5,6,7
h is not 5 from basic rule thus h=4,6,7
f=4,5,6,7
but f is not 5 because h*t=f
so f=6,7,8
now FYH(4,6,7)
* T
———
ZETF(6,7,8)
when you will verify this you get f=8, h=6
all the value can obtain by this

9. rohan418

Since E+Z shoud not give carry,we have possible value of F as 9,8,7,6,5,4,3.
(1)Lets first consider F=9,and solve.
FYH
xT
——
ZETF …………..(1)
——
the product of two no can only be 9 when we take 3*3=9 and 7*7=49.We cannot take these no in consideration because two letters cannot have same no.
So Fcannot be 9….
(2)Lets take F=8,and solve.
2*4=8,2*9=18,3*6=18,4*7=28,6*8=48.
(a)considering first(2*4=8)
T=2 and H=8
putting this in equation (1).
we get,Y=6,Z=1,E=7.
FYH
xW
—-
EKZZ ……………..(2)
—-
Z=1 while having H=8(we cannot get such combination) is not possible from equation(2).
same is the case with H=2,T=8.
(b)Now,considering second(2*9=18)
putting this in equation (1) we cannot get any soution from equation(you can check).
(c)Now,lets consider third(3*6=18)
ie.T=3,H=6.
putting this in equation(1) we get,
Y=4,Z=2,E=5.
using these results in equation(2) we get….
W=7,k=9.
using these all solution in the question we get..
F=8,Y=4,T=3,H=6,Z=2,E=5,W=7,K=9,X=0 ANS.