1. | Which of the following set contains only even numbers ? | |||

(a) A, R, C | (b) A, P, R | (c) P, R, O | (d) O, C, T |

2. | Which of the following set contains odd numbers ? | |||

(a) A, P, R | (b) T, O, P | (c) J, T, C | (d) R, O, C |

3. | Value of A ? | |||

(a) 1 | (b) 2 | (c) 3 | (d) 4 |

```
A P R
x O C T
P U R A
R O J R
R E C U
R A A J A A
As, R x C= _C [ R O J R]
Hence Possible values of R and C are
Case 1 When C={6} then R={2, 4, 8}
Case 2 When R={5} then C={3, 7, 9} Detailed Explanation -Rule 3
At this stage you can also collect one more clue
A P R
x O C T
P U R A
R O J R
R E C U
R A A J A A
i.e. R + R = A
Now proceed further...
```

```
1. A
2. B
3. D
A=4, P=3, R=2, O=5, C=6, T=7, J=9, U=0, E=1
4 3 2
X 5 6 7
3 0 2 4
2 5 9 2
2 1 6 0
2 4 4 9 4 4
```

A P R x O C T P U R A R O J R R E C U R A A J A A As, R x C= _C [ R O J R] Hence Possible values of R and C are Case 1 When C={6} then R={2, 4, 8} Case 2 When R={5} then C={3, 7, 9} Detailed Explanation -Rule 3 At this stage you can also collect one more clue A P R x O C T P U R A R O J R R E C U R A A J A A i.e. R + R = A Now firstly take Case-1 Case 1- C={6} then R={2, 4, 8} take C=6 and R=2 Put C=6 and R=2 and rewrite the problem again. A P 2 x O 6 T P U 2 A 2 O J 2 2 E 6 U 2 A A J A A A P R x O C T P U R A R O J R R E C U R A A J A A At this stage you can easily predict the value of A=4 Put A=4 and rewrite the problem again 4 P 2 x O 6 T P U 2 4 2 O J 2 2 E 6 U 2 4 4 J 4 4 At this you can easily predict the value of T=7 (As, 2 x T= _ 4) (T cannot be equal to 2 as you have already taken R=2) Put T=7 and rewrite the problem. 4 P 2 x O 6 7 P U 2 4 2 O J 2 2 E 6 U 2 4 4 J 4 4 At this stage, you can see 2 + E + 1(carry) = 4 Hence E=1 Now, 4 P 2 x O 2 E 6 U you can see, 2 is present at thousand place, which is only possible when value of O=5 (Value of O cannot be equal to 6,7 as you have already taken these values) Hence put O=5 and E=1 and rewrite the problem. 4 P 2 x 5 6 7 P U 2 4 2 5 J 2 2 1 6 U 2 4 4 J 4 4 Now you can easily solve the problem. 4 3 2 x 5 6 7 3 0 2 4 2 5 9 2 2 1 6 0 2 4 4 9 4 4 [Relax - it's going to take some time to understand the whole concept. If you are facing any difficulty. Please go through the Cryptarithmetic Tutorial.]

You might be interested in this article |

● Cryptarithmetic Problem 17 |

● Cryptarithmetic Problem 15 |

● Cryptarithmetic Tutorial |

● Cryptarithmetic Multiplication Problem |

how to solve those ques in which there is a ques mark in place of alphabet..plz sir help

Here at 10th place R+R=A, which means that A is an even number. now check ques.3, even values of A in option are 2 and 4, which means R= 1 or 2 (A=2R)

now lets R=1, but in first multiplication T*R !=T, so R cannot be 1. hence R=2 and A=4

now in first multiplication T*2=4 which is possible for only 2 values of T(2,7) but T cannot be 2 so T=7

NOw solve it by yourself