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Cryptarithmetic Multiplication 13

Cryptarithmetic-PROBLEM-13

1. Find the value of G + A + S ? 
(a) 12 (b) 13 (c) 14 (d) 15
2. Find the value of 2S + R? 
(a) 9 (b) 5 (c) 10 (d) 12
3. Value of F ? 
(a) 1 (b) 2 (c) 3 (d) 4

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4 comments

    1. Akshay

      S can’t be 6 because it makes F,B,I even digits (2,4,8) and none of the even digit satisfy the rules when a hit and try is made on each.

  1. vikas solanki

    you can proceed like this
    just hint
    S*F=F
    S*B=B
    S*I=I

    POSSIBLE VALUES OF S {6,1}
    IS S=6 THEN POSSIBLE VALUES OF F ,B AND I WILL BE{2,4,8} NOT IN THE SAME ORDER

    IF YOU WILL LOOK INTO MULTIPLICATION
    B + B=T
    IF B=2->T=4 NOT POSSIBLE AS F AND I ,ONE OF THEM WILL HAVE 4
    IF B=4->T=8 NOT POSSIBLE AS ONE OF TWO F AND I WILL HAVE 8
    IF B=8->T=6 NOT POSSIBLE as s=6
    SO REJECT S=6…SO S WILL SURELY BE 1
    G A S
    *B USE UNIT DIGIT METHOD IN THIS B{2,3,4,,,,,,,,9}
    ——–
    S S T B
    ———-

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