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ElitmusZone » Cryptarithmetic Multiplication 11

# Cryptarithmetic Multiplication 11 1. Value of H + S + P ? (a) 10 (b) 11 (c) 12 (d) 13
 2. Which of the following forms a triangle ? (a) H, S, P (b) H, T, O (c) D, U, O (d) U, T, P
 3. Value of 2D + P ? (a) 14 (b) 15 (c) 16 (d) 17

1. Vinay

Plz let us know what happens if we take case 2 while solving….how can we know which case is best to solve.

1. satheesh

if we take case2 then p=5 and p+p=10 ie O=0 WHICH IS NOT TRUE BCOZ IF O=0 THEN EVERYTHING MULTIPLIED BY ZERO WILL BE ZERO

2. Vikas Kumar

You can not predict it which case is write Go on your luck bro.

2. Sandeep

How do we get and. 2.
How triangle is formed by HTO

3. Sandeep

Is it because 16+9=25?
Ans 2

4. Shujayat Ali1

@Sandeep…. actually we are not using here pythagoras theorem to check formation of triangle.

We are applying here…. (“”in a triangle the sum of two sides must be greater than the third side””)

a) H=3,S=8,P=2 (not forming triangle because H+P is not greater than S)
b) H=3,T=5,O=4 (here it is following the rule..in a triangle the sum of two sides must be greater than the
third side)
c) D=6,U=1,O=4 (it is not following the rule…in a triangle the sum of two sides must be greater than the third
side)
d) U=1,T=5,P=2 ((it is not following the rule…in a triangle the sum of two sides must be greater than the third
side)

5. vikas solanki

we can proceed like this also AND BEST WAY I THINK TO LEARN THESE MULTIPLICATION IS DONOT LOOK FOR OPTION and just follow unit digit method

as we can easily see U is =1
and d*p=p
possible of values for P and D is
P{5} D{3,7,9,}
P{2,4,8} D{6}
WE CAN EASILY REJECT FIRST SET OF VALUES IF YOU WILL SEE
P+P=0
AND IF P=5 THEN O SHOULD BEE ZERO. BUT O CANT BE ZERO IF YOU OBSERVE THE MULTIPLIACTION
SO PROCEED WITH SECOND SET OF VALUES AND HIT ANS TRIAL WITH
P{2,4,6}
D{6}